2[3-(3-5r)]-r=-6+3(2+3r)

Solution for 2[3-(3-5r)]-r=-6+3(2+3r) equation:

Simplifying
2[3 + -1(3 + -5r)] + -1r = -6 + 3(2 + 3r)
2[3 + (3 * -1 + -5r * -1)] + -1r = -6 + 3(2 + 3r)
2[3 + (-3 + 5r)] + -1r = -6 + 3(2 + 3r)

Combine like terms: 3 + -3 = 0
2[0 + 5r] + -1r = -6 + 3(2 + 3r)
2[5r] + -1r = -6 + 3(2 + 3r)

Remove brackets around [5r]
2 * 5r + -1r = -6 + 3(2 + 3r)

Multiply 2 * 5
10r + -1r = -6 + 3(2 + 3r)

Combine like terms: 10r + -1r = 9r
9r = -6 + 3(2 + 3r)
9r = -6 + (2 * 3 + 3r * 3)
9r = -6 + (6 + 9r)

Combine like terms: -6 + 6 = 0
9r = 0 + 9r
9r = 9r

Add '-9r' to each side of the equation.
9r + -9r = 9r + -9r

Combine like terms: 9r + -9r = 0
0 = 9r + -9r

Combine like terms: 9r + -9r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.